SOLUTION: I'm stuck on how to solve this one (2X^3-7X^2-4)/(2X-3) I set it up in long division and so far i got (2X-3/2X^3-7X^2-4) I put x^2 above 7X^2 and i multiplied it makin

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Question 58298: I'm stuck on how to solve this one
(2X^3-7X^2-4)/(2X-3)
I set it up in long division and so far i got
(2X-3/2X^3-7X^2-4)
I put x^2 above 7X^2 and i multiplied it making it look like this now
2x^3-7x^2 minus 2x^3-7x^2=4X^2-4. i dont know what to do anymore.

Answer by ankor@dixie-net.com(12704) (Show Source):
You can put this solution on YOUR website!
(2X^3-7X^2-4)/(2X-3)
Your Answer:
(2X^3-7X^2-4)/(2X-3)
:
Using long division, note that each degree of the equation has to be placed so 0x is inserted:
[Used ......... to keep things lined up]
...............................x^2 - 2x - 3
............---------------------------
(2x-3) | 2x^3 - 7x^2 - 0x - 4
................2x^3 - 3x^2
................-------------
..............................-4x^2 - 0x
..............................-4x^2 + 6x
...............................-----------
...........................................-6x - 4
...........................................-6x + 9
...........................................--------
..................................................-13
:
The solution: x^2 - 2x - 3; remainder -13/(2x-3)