SOLUTION: Factor b(b-2)(b+1)- 3

SOLUTION: Factor b(b-2)(b+1)- 3 - 3b

Question 577465: Factor b(b-2)(b+1)- 3 - 3b
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Factor
b(b-2)(b+1)- 3 - 3b
-----
b(b-2)(b+1)-3(1+b)
----
Common factor: (b+1)
---
Factoring you get:
(b+1)[b(b-2)-3]
-----
= (b+1)(b^2-2b-3)
-----
= (b+1)(b-3)(b+1)
----
= (b+1)^2*(b-3)
====================
Cheers,
Stan H.
====================
RELATED QUESTIONS
factor completely... (answered by nerdybill)

1/2a-1/3b; -a+2/3b;... (answered by ikleyn)

divide... (answered by josgarithmetic,MathTherapy)

Factor the given polynomial b^3 � 3b^2 � 4b +... (answered by jim_thompson5910)

Divide:... (answered by stanbon,algebrahouse.com)

2b(b^2+3b+1) (answered by jim_thompson5910)

-3b/b-2 =... (answered by fractalier)

1/3(9b+1)=b-1 3b+1/3=b-1 -b -b 2b+1/3=-1 +1 +1... (answered by tjnw79)