SOLUTION: it says write a polynomial function of least degree that has real coefficient, the given zeros, and leading coefficients of 1.
with these three numbers... -1, -2, -3
and th
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Question 576103: it says write a polynomial function of least degree that has real coefficient, the given zeros, and leading coefficients of 1.
with these three numbers... -1, -2, -3
and these... 3, -3, 2i
then after you write a polynomial function multiply it out, do not leave in factored form.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
If 
is a zero of a polynomial equation, then 
is a factor of the polynomial. Complex zeros always come in conjugate pairs, that is if 
is a zero, then 
is also a zero.
For your second problem, 
is a zero, so 
is also a zero. Hence your four factors are:
(x\ +\ 3)(x\ +\ 2i)(x\ -\ 2i)\ =\ 0)
You can multiply out the factors for yourself. Hint: The product of two conjugates is the difference of two squares. Hint #2: Don't forget 
-- that will make the product of the two complex factors the SUM of two squares and eliminate the 
s.
John
My calculator said it, I believe it, that settles it
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