SOLUTION: factoring trinomials by grouping 6c^3+c^2-7c

Question 57317: factoring trinomials by grouping
6c^3+c^2-7c
Found 2 solutions by stanbon, funmath:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
6c^3+c^2-7c
c(6c^2+c-7)
c(6c^2+7c-6c-7)
c(c(6c+7)-(6c+7))
c(6c+7)(c-1)
Cheers,
Stan H.

Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
The standard form of a quadratic equation is: , when I refer to a, I mean the coefficient of x^2, when I say b, I mean the coefficient of x, and when I say c, I am referring to the number without an x.
factoring trinomials by grouping

First factor out your GCF,c.

Now we need to replace b with two numbers that multiply together to give you a*c but add together to give you b.
Our a=6, b=1, and c=-7 and a*c=6(-7)=-42
Two numbers that multiply to get -42, but add to get 1 are: 7 and -6
7*-6=-42 and 7-6=1
Replace c with 7c-6c

Group the first two terms and the second two terms
Factor the GCF out of each parenthesis.
Factor out (6c+7) because both c and -1 have that as a cofactor.

Happy Calculating!!!!
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