SOLUTION: Here is another problem with addition just in case the steps are different than subtraction. (4y/y^2+6y+5)+(2y/y^2-1)

Question 56144This question is from textbook Beginning Algebra
: Here is another problem with addition just in case the steps are different than subtraction.
(4y/y^2+6y+5)+(2y/y^2-1) This question is from textbook Beginning Algebra

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(4y/y^2+6y+5)+(2y/y^2-1)
Factor where you can to get:
4y/[(y+5)(y+1)] + 2y/[(y-1)(y+1)]
The LCD is (y+5)(y+1)(y-1)]
Rewrite each fraction with LCD as its denominator:
(4y)(y-1)/LCD + 2y(y+5)/LCD
Combine the numerators over the LCD
[4y^2-4y+2y^2+10y]/LCD
[6y^2+6y]/LCD
[6y(y+1)]/LCD
Cancel the common (y+1) factors to get:
6y/[(y+5)(y-1)]
Cheers,
Stan H.

RELATED QUESTIONS
Here it is again! I know how to do this, I just don't have the resourse, can someone help (answered by Edwin McCravy)

My answer is not changing much from the question...please help me with this. Complete in... (answered by Nate)

Please tell me the problem with this equation. 4y - (4+y) + 24=6y + 20 + 4y 4y - 4y +... (answered by sudhanshu_kmr)

Can you help me with this problem? Again, I am having touble with the common... (answered by rapaljer)

4y + 2y ---------- ---------- y^2 + 6y + 5 y^2 - 1 I am (answered by checkley71)

i have a few questions here i jut do not understand they are from different sections... (answered by stanbon)

Add and write in simplest form: 4y/y^2+6y+5 added to 2y/y^2-1 All of this math is new to (answered by Edwin McCravy)

Could you please help me figure out this problem. 4y/y^2+6y+5 + 2y/y^2-1 I keep... (answered by fractalier)

add the expression, finish in simplest form 4y/y^2+6y+5 + 2y/y^2-1 Thanks in... (answered by rchill)