SOLUTION: Hello, I need some assistance with problems such as this. I can figure out the LCD but my text then tells me to build up. Which according to the book means to build up each fractio

Question 56142This question is from textbook Beginning Algebra
: Hello, I need some assistance with problems such as this. I can figure out the LCD but my text then tells me to build up. Which according to the book means to build up each fraction to an equivalent fraction with the LCD as the denominator. I don't understand what that means.
(3/x^2+4x+3)- (1/x^2-9)
This question is from textbook Beginning Algebra

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
(3/X^2+4X+3)-(1/X^2-9)
(3+4X^3+3X^2)/X^2-(1-9X^2)/X^2
(3+4X^3+3X^2-1+9X^2)/X^2
(3-1+4X^3+3X^2+9X^2)/X^2
(2+4X^3+12X^2)/X^2
(4X^3+12X^2+2)/X^2
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