SOLUTION: 1.Factor by grouping, if possible, and check. 20g^3-4g^2-25g+5 and completely show your work.

Question 555019: 1.Factor by grouping, if possible, and check. 20g^3-4g^2-25g+5 and completely show your work.
Found 2 solutions by fcabanski, sarhjo29:
Answer by fcabanski(1391) (Show Source): You can put this solution on YOUR website!
20g^3-4g^2-25g+5 | Separate into separate terms.
(20g^3 - 4g^2) (-25g+5) |factor each
4g^2(5g-1) (-5(5g-1)
(4g^2-5)(5g-1) | Plug in 0, 1 and -1 to see both expressions are the same.

35x^2-57x-44 | Think of factors for 35 and for 44. 5+7=35 and 4*11=44 and 2*22=44.
(5x )(7x ) |Can 4 and 11 or 2 and 22 fit in there to give -57x and -44. Yes.
(5x - 11)(7x + 4) | 4*-11=-44 and -11*7x+4*5x=-57. Check some x values to see it's the right factor.

3t^2-3 | 3 is prime so the terms have to be 3t and t and 3 and 1.
(3t-3)(t+1)

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Answer by sarhjo29(2) (Show Source): You can put this solution on YOUR website!
Factor by grouping, if possible, and check. 20g^3-4g^2-25g+5 and completely show your work.
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