SOLUTION: Hello: Please help me solve the following problem (thank you)
divide
{{{8x^3+ 8y^3}}}divided by {{(4x^2-4xy+4y^2}}}
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Question 55309: Hello: Please help me solve the following problem (thank you)
divide
divided by {{(4x^2-4xy+4y^2}}}
Found 2 solutions by funmath, stanbon:
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
divide
Factor out the GCF in the numerator and denominator:
The formula for factoring the sum of cubes is:.
Cancel the things that match between the numerator and denominator:
That's usually all you need, but you could distribute the 2 and get 2x+2y.
Happy Calculating!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(8x^3+ 8y^3) divided by (4x^2-4xy+4y^2)
[8(x^3+y^3}]/[4(x^2-x+y^2)]
Reduce the 8/4 to get:
[2(x+y)(x^2-xy+y^2)]/[x^2-xy+y^2]
Cancel the x^2-xy+y^2 to get:
2x+2y
Cheers,
Stan H.
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