SOLUTION: factoring polynomials [Sum of cubes]: x^3 + y^3 = (x + y)(x^2 − xy + y^2) [Difference of cubes]: x^3 - y^3 = (x-y)(x^2 + xy + y^2) problem: 250x^4-54x
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-> SOLUTION: factoring polynomials [Sum of cubes]: x^3 + y^3 = (x + y)(x^2 − xy + y^2) [Difference of cubes]: x^3 - y^3 = (x-y)(x^2 + xy + y^2) problem: 250x^4-54x
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Question 552011
:
factoring polynomials
[Sum of cubes]: x^3 + y^3 = (x + y)(x^2 − xy + y^2)
[Difference of cubes]: x^3 - y^3 = (x-y)(x^2 + xy + y^2)
problem:
250x^4-54x
Found 2 solutions by
Earlsdon, solver91311
:
Answer by
Earlsdon(6287)
(
Show Source
):
You can
put this solution on YOUR website!
Factor:
Factor 2x.
Now factor the difference of cubes.
Answer by
solver91311(16877)
(
Show Source
):
You can
put this solution on YOUR website!
Factor out
leaving you with:
And since
and
, just follow the pattern for the difference of two cubes.
BTW, the cubes factorizations are much easier to remember as one statement rather than two as you gave them:
And the key to remembering the way the signs go is to remember San Diego Padres -- SDP -- Same, Different, Positive.
John
My calculator said it, I believe it, that settles it
(
