# SOLUTION: factoring polynomials [Sum of cubes]: x^3 + y^3 = (x + y)(x^2 &#8722; xy + y^2) [Difference of cubes]: x^3 - y^3 = (x-y)(x^2 + xy + y^2) problem: 250x^4-54x

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: factoring polynomials [Sum of cubes]: x^3 + y^3 = (x + y)(x^2 &#8722; xy + y^2) [Difference of cubes]: x^3 - y^3 = (x-y)(x^2 + xy + y^2) problem: 250x^4-54x      Log On

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 Algebra: Polynomials, rational expressions and equations Solvers Lessons Answers archive Quiz In Depth

 Question 552011: factoring polynomials [Sum of cubes]: x^3 + y^3 = (x + y)(x^2 − xy + y^2) [Difference of cubes]: x^3 - y^3 = (x-y)(x^2 + xy + y^2) problem: 250x^4-54xFound 2 solutions by Earlsdon, solver91311:Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!Factor: Factor 2x. Now factor the difference of cubes. Answer by solver91311(16877)   (Show Source): You can put this solution on YOUR website! Factor out leaving you with: And since and , just follow the pattern for the difference of two cubes. BTW, the cubes factorizations are much easier to remember as one statement rather than two as you gave them: And the key to remembering the way the signs go is to remember San Diego Padres -- SDP -- Same, Different, Positive. John My calculator said it, I believe it, that settles it