SOLUTION: Andrew factored the expression as -12x^3 - 28x^2 - 36x as -4x(3x^2 - 7x + 9).
But when Melissa applied the distributive law and multiplied out -4x(3x^2 - 7x + 9), she got -12x^3
Algebra.Com
Question 550940: Andrew factored the expression as -12x^3 - 28x^2 - 36x as -4x(3x^2 - 7x + 9).
But when Melissa applied the distributive law and multiplied out -4x(3x^2 - 7x + 9), she got -12x^3 + 28x^2 - 36x; thus, Andrew’s solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
note where he factored out -4x from -28x^2 and got - 7x, it should have been +7x
RELATED QUESTIONS
I really need help please with this...
Andrew factored the expression -12x^3-28x^2-36x (answered by Alan3354)
Andrew factored the expression 28x^3-42x^2+35x as 7x(4x^4+6x-5). But when Melissa applied (answered by ankor@dixie-net.com)
Andrew factored the expression28x^2-42x^2+35x as 7x(4x^2+6x-5) . But when Melissa applied (answered by MathLover1)
8. Andrew factored the expression -6x^3+9x^2-3x as -3x(2x^2-3x-1) . But when Melissa... (answered by Gogonati)
Andrew factored the expression -6x^3+9x^2-3x as -3x(2x^2-3x-1) but when Melissa applied... (answered by richard1234)
Andrew factored the expression 28x³-6x²-10x as 2x(14x³-3x²-5x). But when Melissa applied... (answered by richard1234)
Andrew factored the expression -30x^3-9x^2-3x as -5x(6x^2-2x-1) . But when Melissa... (answered by stanbon)
Andrew factored the expression -30x^3-9x^2-3x as -5x(6x^2-2x-1) . But when Melissa... (answered by richwmiller)
Andrew factored the expression -30x^3-9x^2-3x as -5x(6x^2-2x-1). But when Melissa... (answered by edjones)