SOLUTION: Essay; show all work.Add the following polynomials: (1/10x2 – 1/2x(-3/10))+(1/2x2+1/4x(-1/5))
Solving:
(1/10-1/2)x2 + (-1/2 -1/4)x+(-3/10-(-1/5))= (-2/5)x2 + (-3/4) + (1/5)= -1
Algebra.Com
Question 548846: Essay; show all work.Add the following polynomials: (1/10x2 – 1/2x(-3/10))+(1/2x2+1/4x(-1/5))
Solving:
(1/10-1/2)x2 + (-1/2 -1/4)x+(-3/10-(-1/5))= (-2/5)x2 + (-3/4) + (1/5)= -19/20
Answer:
-19/20
Essay; show all work. Find the product: (1/3x^2(-2/3))*(1/2x -1/2)
Solving:
1/3x2 * 1/2x* -2/3 -1/2= 1/6x3 * 1/3
Answer:
1/6x3 * 1/3
What am I doing wrong???
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
I have no idea what you're doing. Let's start from the beginning. First, you should make your notation clear by correctly placing parentheses, and don't place operations such as * or + unless you clearly know what number/expression you want to use. Knowing LaTeX or the notation on algebra.com can help (here I use LaTeX since it is more widely used, and is neater).
You want to do the operation
) + (\frac{1}{2}x^2 + \frac{1}{4}x(-\frac{1}{5})))
.
First, do the innermost operations (in this case, multiplying variable expressions by constants) to get
 + (\frac{1}{2}x^2 - \frac{1}{20}x))
Then add. You cannot combine x^2 and x terms together, similar to the fact that you cannot combine apples and oranges and obtain apples. Adding, we get
x^2 + (\frac{3}{20} - \frac{1}{20})x)
---------------------
For the multiplication one, we multiply the -2/3 with the 1/3, so our expression is equivalent to
(\frac{1}{2}x - \frac{1}{2}))
Then multiply. Be careful about the negative signs.
(\frac{1}{2}x) + (-\frac{2}{9}x^2)(-\frac{1}{2}))
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