SOLUTION: 9x^4+9x^3-22x^2-4x+8=0 solve for all zeros, real and complex numbers

Question 548212: 9x^4+9x^3-22x^2-4x+8=0 solve for all zeros, real and complex numbers
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
9x^4+9x^3-22x^2-4x+8=0 solve for all zeros, real and complex numbers
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The sum of the coefficients is zero so x=1 is a root.
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Use synthetic division to find the other roots:
1)....9.....9....-22....-4....8
........9.....18....-4....-8...|..0
I graphed y = 9x^3+18x^2-4x-8 and found
roots at x = -2/3, x = 2/3, x = -2
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Cheers,
Stan H.
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