SOLUTION: find the vertex
f(x) = -10x^2-140x+495
Algebra.Com
Question 542287: find the vertex
f(x) = -10x^2-140x+495
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the vertex
f(x) = -10x^2-140x+495
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The vertex occurs where x = -b/(2a) = 140/(2*-10) = -7
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f(-7) = -10(-7)^2-140(-7)+495 = 985
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Vertex: (-7,985)
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Cheers,
Stan H.
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