SOLUTION: I received these problems from my instructor which I can't find in the text: 1.) 2/(3x) + 3/(2x) = 2.) 1/(x + 1) + 1/(x-1) = 3.) x/2 + 2/x = Can someone help me with th

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I received these problems from my instructor which I can't find in the text: 1.) 2/(3x) + 3/(2x) = 2.) 1/(x + 1) + 1/(x-1) = 3.) x/2 + 2/x = Can someone help me with th      Log On


   

Question 54139: I received these problems from my instructor which I can't find in the text:
1.) 2/(3x) + 3/(2x) =
2.) 1/(x + 1) + 1/(x-1) =
3.) x/2 + 2/x =
Can someone help me with these? I've even tried using the equation calculator but tt comes up with a syntax error. I haven't had math in a while so any explanations of the rule will be helpful as well.
Thanks
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
There's nothing on the other side of the = sign, so you can't solve them. These are expressions that need to be simplified into one fraction. In order to combine them, you have to have a common denominator.
1.
2%2F3x%2B3%2F2x Has a LCD (lowest common denominator) of 6x, it is the smallest number that both 3x and 2x both divide evenly into. What ever you do to the denominators to get 6x you have to do to the numerator.
2%2A2%2F%282%2A3x%29%2B3%2A3%2F%283%2A2x%29
4%2F6x%2B9%2F6x Combine the numerators and keep the denominator the same.
%284%2B9%29%2F6x
highlight%2813%2F6x%29
2.
1%2F%28x%2B1%29%2B1%2F%28x-1%29 The LCD is (x+1)(x-1).
%28x-1%29%2A1%2F%28%28x%2B1%29%28x-1%29%29%2B%28x%2B1%29%2A1%2F%28%28x%2B1%29%28x-1%29%29
%28x-1%29%2F%28%28x%2B1%29%28x-1%29%29%2B%28x%2B1%29%2F%28%28x%2B1%29%28x-1%29%29
%28%28x-1%29%2B%28x%2B1%29%29%2F%28%28x%2B1%29%28x-1%29%29
highlight%282x%2F%28%28x%2B1%29%28x-1%29%29%29
3.
x%2F2%2B2%2Fx LCD is 2x.
x%2Ax%2F%282%2Ax%29%2B2%2A2%2F%282%2Ax%29
x%5E2%2F2x%2B4%2F2x
highlight%28%28x%5E2%2B4%29%2F2x%29
Happy Calcualting!!!