SOLUTION: Factor: a) x^2-y^2+3x+y+2 b) 2x^2-3y^2-5xy+x+11y-6 c) x^2(y-z)+y^2(z-x)+z^2(x-y) I could only begin c) with expanding out the whole expression to: x^2(y)

SOLUTION: Factor: a) x^2-y^2+3x+y+2 b) 2x^2-3y^2-5xy+x+11y-6 c) x^2(y-z)+y^2(z-x)+z^2(x-y) I could only begin c) with expanding out the whole expression to: x^2(y) - x^2(z) + y^2(

Question 541131: Factor:
a) x^2-y^2+3x+y+2
b) 2x^2-3y^2-5xy+x+11y-6
c) x^2(y-z)+y^2(z-x)+z^2(x-y)
I could only begin c) with expanding out the whole expression to:
x^2(y) - x^2(z) + y^2(z) - xy^2 - yz^2
I could not even attempt a) or b) and as mentioned above, I began c) with the expansion shown above.
Any assistance on these three problems would be greatly appreciated.
Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
a) x^2-y^2+3x+y+2
Rewrite the equation
x^2+3x-y^2+y +2
complete the squares by splitting 2
9/4 -1/4 = 8/4 =2
(x^2+3x+9/4) -(y^2-y +1/4)
(x+3/2)^2- (y-1/2)^2
Difference of two squares
(x+3/2+y-1/2)(x+3/2-y+1/2)
(x+y+1)(x-y+2)
----------------------
b. It is a diophantine equation. to solve it there is a procedure. please look on net

c) x^2(y-z)+y^2(z-x)+z^2(x-y)
Using the direct formula for cyclic expressions
=-(x-y)(y-z)(z-x)
-
RELATED QUESTIONS
(x+y+z)^2=? (answered by jim_thompson5910)

x+y+z=-x^2-y^2+z... (answered by greenestamps,Alan3354)

x + 3y + z= 6 3x + y - z= -2 2x + 2y - z =... (answered by stanbon)

x+3y+z=6 3x+y-z=-2... (answered by ewatrrr)

Solve using addition method x+3y+z=6 3x+y-z=-2... (answered by Alan3354)

2x +y - z=4,3x +5y +z=16,x-2y-5z=3. x+2y+z=4,x+3y-2z=2 , 3x +y+2z =6 c (answered by Alan3354)

Solve each of these system of equations. 1) x + 2y + z = 10 2x - y + 3z = -5 (answered by Alan3354)

Solve the system: x + y - z = 2 2x + y + z = 3 3x... (answered by Alan3354)