SOLUTION: (x^3-1)/(x^2+1) divided by (9x^2+9x+9)/(x^2-x). THis problem is giving me a real hard time. I cannot seem to factor the 9x^2+9x+9 to anything less that 9(x^2+x+1) which does not ca
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Question 53255This question is from textbook Elementary and Intermediate Algebra
: (x^3-1)/(x^2+1) divided by (9x^2+9x+9)/(x^2-x). THis problem is giving me a real hard time. I cannot seem to factor the 9x^2+9x+9 to anything less that 9(x^2+x+1) which does not cancel anything out. Am I doing something wrong?
This question is from textbook Elementary and Intermediate Algebra
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
First flip the second fraction over and multiply:
Then factor. The numerator in the first fraction is a difference between two cubes can be factored:
in your case a=x and b=1.
cancels and we have:
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