+  + 2x

Write the term 2x as , so all terms will be fractions:

 +  + 

The LCD is {x+3)(x-2).  We must get all three fractions to have
the LCD for the denominator by multiplying by unit fractions.

The denominator of the first fraction needs to be multiplied by 
(x-2) to become the LCD, so we multiply the first fraction by 
the unit fraction 

The denominator of the second fraction needs to be multiplied by 
(x+3) to become the LCD, so we multiply the second fraction by 
the unit fraction 

The denominator of the third fraction needs to be multiplied by 
(x+3)(x-2) to become the LCD, so we multiply the first fraction by 
the unit fraction 


· + · + ·


 +  + 

Multiply the tops out but not the bottoms:

 +  + 

 +  + 

Since all the deminators are equal to the LCD, we write the sum of the
numerators over the LCD:



Remove the parentheses on top:



Collect like terms in the top and arrange in descending order:



Edwin