SOLUTION: Solve. 1. v^2-4v=0 2. a^2+13a+40=0 3.(11w+8)(3w-9)=0 4. 81b^6-3t^6 5. 9g^2+18gp+8p^2

Question 521555: Solve.
1. v^2-4v=0
2. a^2+13a+40=0
3.(11w+8)(3w-9)=0
4. 81b^6-3t^6
5. 9g^2+18gp+8p^2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve.
1. v^2-4v=0
---
v(v-4) = 0
v = 0 or v = 4
-----------------------
2. a^2+13a+40=0
a^2+5a+8a+40 = 0
a(a+5)+8(a+5) = 0
(a+5)(a+8) = 0
a = -5 or a = -8
-----------------------
3.(11w+8)(3w-9)=0
w = -8/11 or w = 9/3 = 3
----------------------------
4. 81b^6-3t^6
3[27b^6-t^6]
= 3[(3b^3)^2-(t^3)^2]
= 3[(3b^3-t^3)(3b^3+t^3)
They might want you to factor these as the sum
and the difference of cubes; it gets pretty lengthy.

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5. 9g^2+18gp+8p^2
= 9q^2+12qp+6qp+8p^2
= 3q(3q+4p) + 2p(3q+4p)
= (3q+4p)(3q+2p)
Comment: This one is correct as it stands.
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Cheers,
Stan H.
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Cheers,
Stan H.

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