SOLUTION: i need help please 4a(9a+3) im not sure if im supposed to distribute the 4a
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Question 514725: i need help please 4a(9a+3) im not sure if im supposed to distribute the 4a
Found 3 solutions by jim_thompson5910, umail08, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
4a(9a+3)
4a(9a)+4a(3) ... distribute 4a
36a^2+12a ... multiply
Answer by umail08(87) (Show Source): You can put this solution on YOUR website!
4a(9a+3) … use the distributive property
36a^2 + 12a
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
i need help please 4a(9a+3) im not sure if im supposed to distribute the 4a
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Yes
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4a(9a+3) = 36a^2 + 12a
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Cheers,
Stan H.
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