SOLUTION: Hey Tutors! If you have time, could you please help me with this problem? Thanks! "Find at least one solution of x^2-x=12" - student in need :)

SOLUTION: Hey Tutors! If you have time, could you please help me with this problem? Thanks! "Find at least one solution of x^2-x=12" - student in need :)

Algebra.Com

Question 50771: Hey Tutors!
If you have time, could you please help me with this problem? Thanks!
"Find at least one solution of x^2-x=12"

- student in need :)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^2-x=12
x^2-x-12=0
(x-4)(x+3)=0
x-4=0 or x+3=0
x=4 or x=-3
Cheers,
Stan H.
RELATED QUESTIONS
hey i have another problem for you to help me out with if you could? F street has an... (answered by 303795)

Could you please help me with this problem Find the inverse of f(x)= {{{4x^3-8}}}... (answered by rapaljer)

could you please help me with this one solve. elimate fraction thanks for you help (answered by jim_thompson5910)

hey please help me with this problem,and if possible can you show me the work that leads... (answered by jim_thompson5910)

Find the directrix, the focus and the roots of the parabola y=x^2 - 5x + 4 Please... (answered by KnightOwlTutor)

Could you please help me with this? It's been a long time. Thanks! 2(x-y)=8 where... (answered by DWL)

Could you please help me with the following problem? I can't seem to work this one out. (answered by mananth)

Hey, If you could help me remember how to do this type of problem it would be AWESOME! (answered by John10)

Please help me solve this word problem: Stu has twice as much money invested in stocks (answered by checkley77)