SOLUTION: Factor completely 10x^4 - 11x^3 + 23x^2 + 23x

SOLUTION: Factor completely 10x^4 - 11x^3 + 23x^2 + 23x - 21

Question 49772: Factor completely
10x^4 - 11x^3 + 23x^2 + 23x - 21
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
10x^4 - 11x^3 + 23x^2 + 23x - 21
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f(-1)=0 which means (x+1) is a factor.
Using synthetic division you can find the other
factor: (10x^3-21x^2+44x-21)
Using graphing I find f(0.6)= 0 which means
(10x-6) is a factor.
Dividing you find the quadratic factor x^2-1.5x+3.5
Using the quadratic equation you can find the zeroes
of this quadratic and the remaining factors.
Cheers,
Stan H.
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