SOLUTION: f(x)=25xsquare2+20x+4 find the y intercepts and x intercepts

Question 491888: f(x)=25xsquare2+20x+4 find the y intercepts and x intercepts
Answer by ccs2011(207) (Show Source): You can put this solution on YOUR website!
Intercepts can be found by plugging in zero for the other variable since anywhere on y-axis, x=0 and anywhere on x-axis, y=0
Y-intercept: set x=0
--> y = 0+0+4 = 4
Y-intercept is the point (0,4), this is where the graph crosses the y-axis
X-intercept: set y=0
--> 25x^2 +20x +4 = 0
I will use the quadratic solver to show how to find x:

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=0 is zero! That means that there is only one solution: .
Expression can be factored:

Again, the answer is: -0.4, -0.4. Here's your graph:

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