SOLUTION: AGAIN, I'm getting stuck here! Right when I thought I knew it... Solve 6x^2 + 3x – 12 = 2 – 2x Okay, so I subtracted 2-2x from both sides and end up with 6x^2+5x-14 Now, do

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: AGAIN, I'm getting stuck here! Right when I thought I knew it... Solve 6x^2 + 3x – 12 = 2 – 2x Okay, so I subtracted 2-2x from both sides and end up with 6x^2+5x-14 Now, do       Log On


   



Question 490779: AGAIN, I'm getting stuck here! Right when I thought I knew it...
Solve 6x^2 + 3x – 12 = 2 – 2x
Okay, so I subtracted 2-2x from both sides and end up with 6x^2+5x-14
Now, do I divide by 6? I don't understand how that would work, and there are no factors of 14. I'm looking at my teacher's notes from last year and they aren't helping.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression 6x%5E2%2B5x-14, we can see that the first coefficient is 6, the second coefficient is 5, and the last term is -14.


Now multiply the first coefficient 6 by the last term -14 to get %286%29%28-14%29=-84.


Now the question is: what two whole numbers multiply to -84 (the previous product) and add to the second coefficient 5?


To find these two numbers, we need to list all of the factors of -84 (the previous product).


Factors of -84:
1,2,3,4,6,7,12,14,21,28,42,84
-1,-2,-3,-4,-6,-7,-12,-14,-21,-28,-42,-84


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -84.
1*(-84) = -84
2*(-42) = -84
3*(-28) = -84
4*(-21) = -84
6*(-14) = -84
7*(-12) = -84
(-1)*(84) = -84
(-2)*(42) = -84
(-3)*(28) = -84
(-4)*(21) = -84
(-6)*(14) = -84
(-7)*(12) = -84

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 5:


First NumberSecond NumberSum
1-841+(-84)=-83
2-422+(-42)=-40
3-283+(-28)=-25
4-214+(-21)=-17
6-146+(-14)=-8
7-127+(-12)=-5
-184-1+84=83
-242-2+42=40
-328-3+28=25
-421-4+21=17
-614-6+14=8
-712-7+12=5



From the table, we can see that the two numbers -7 and 12 add to 5 (the middle coefficient).


So the two numbers -7 and 12 both multiply to -84 and add to 5


Now replace the middle term 5x with -7x%2B12x. Remember, -7 and 12 add to 5. So this shows us that -7x%2B12x=5x.


6x%5E2%2Bhighlight%28-7x%2B12x%29-14 Replace the second term 5x with -7x%2B12x.


%286x%5E2-7x%29%2B%2812x-14%29 Group the terms into two pairs.


x%286x-7%29%2B%2812x-14%29 Factor out the GCF x from the first group.


x%286x-7%29%2B2%286x-7%29 Factor out 2 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x%2B2%29%286x-7%29 Combine like terms. Or factor out the common term 6x-7


So 6x%5E2%2B5x-14 factors to %28x%2B2%29%286x-7%29.


In other words, 6x%5E2%2B5x-14=%28x%2B2%29%286x-7%29.


Note: you can check the answer by expanding %28x%2B2%29%286x-7%29 to get 6x%5E2%2B5x-14 or by graphing the original expression and the answer (the two graphs should be identical).



I'll let you take it from here.


If you need more help, feel free to email me at
jim_thompson5910@hotmail.com

Thanks,
Jim