# SOLUTION: The length of a rectangle is eight times its width. If the length was decreased by 10 meters and the width was decreased by 2 meters, the area would be decreased by 162 square mete

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: The length of a rectangle is eight times its width. If the length was decreased by 10 meters and the width was decreased by 2 meters, the area would be decreased by 162 square mete      Log On

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 49004: The length of a rectangle is eight times its width. If the length was decreased by 10 meters and the width was decreased by 2 meters, the area would be decreased by 162 square meters. Find the original dimensions. Please explain.Answer by Paul(988)   (Show Source): You can put this solution on YOUR website!Length = 8x Width = x Decreased length = 8x-10 Decreased width = x-2 Original area = (8x)(x)= Decreased area = EQUATION: -26x=-182 x=7 8(7)=56 Hence, the width is 7m and the length is 56m. Paul.