SOLUTION: Factor completely. {{{ 7x^3-4x^2-8x }}} **So far I have factored an x out of all terms {{{ x(7x^2-4x-8) }}} I am not sure how to factor the rest

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Question 484553: Factor completely.

**So far I have factored an x out of all terms

I am not sure how to factor the rest
Found 2 solutions by stanbon, jorel1380:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
7x^3-4x^2-8x
----
= x(7x^2-4x-8)
---
There is no further factoring
which would simplify the form.
=======================
Cheers,
Stan H.
Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
x(7x^2-4x-8)=
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=240 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.39228095605926, -0.820852384630691. Here's your graph:

So the answer is 1.39228095605926(x) or -0.820852384630691(x)
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