SOLUTION: how do i factor a polynomial that douse not have a coaficiant of 1 like {{{ 9x^2+24x+16}}}

SOLUTION: how do i factor a polynomial that douse not have a coaficiant of 1 like {{{ 9x^2+24x+16}}}

Algebra.Com

Question 483381: how do i factor a polynomial that douse not have a coaficiant of 1 like
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
=(3x+4)(3x+4)
You factor in the same way, but you don't just use 1 as the coefficient of your x variable..
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