SOLUTION: can you help me to solve this problem please?
{{{(2x-1)^(2/3)=16}}}
Algebra.Com
Question 482539: can you help me to solve this problem please?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
take the cube of both sides of the equation
4x^2-4x+1=4096
4x^2-4x-4095=0
Find the roots of the equation by quadratic formula
a= 4 ,b= -4 ,c= -4095
b^2-4ac= 16 + 65520
b^2-4ac= 65536
x1=( 4 + 256 )/ 8
x1= 32.5
x2=( 4 -256 ) / 8
x2= -31.5
The roots are 32.5 & -31.5
32.5 satisfies the equation
CHECK
((2*32.5)-1)^(2/3)=16
m.ananth@hotmail.com
RELATED QUESTIONS
Can you please help me solve this algebra problem.... (answered by jim_thompson5910)
can you please help me to solve this problem 6-4(2x+1)=4+2(x-6)+3... (answered by fion23)
Can you please help me to solve this equation:... (answered by edjones)
Can you please help me solve this problem?... (answered by Edwin McCravy)
Can you please help me solve this problem?
2x^2> -5x + 3
(answered by mananth)
Stuck with this problem. Can you please help me... (answered by Alan3354)
Please help me solve the equation (2x-1)^2=121.Can you please show me the steps to... (answered by Alan3354)
I having trouble getting this radical expression to solve. I do not have the root symbol... (answered by Fombitz,ankor@dixie-net.com)
I don't know what to do can you please help me?
1 over 3 (2x divided by 12)=16
(answered by richwmiller)