Hi,

x^3+8x^2+2x+16  Note: x = -8 is a root, thus(x+8) one factor

Applying synthetic division: (x^3+8x^2+2x+16)/(x+8) = x^2 + 2

-8	1	8	2	16

		-8	0	-16

	1	0	2	0

x^3+8x^2+2x+16 = (x+8)(x^2+2) = x^3 + 8x^2 + 2x + 16

                  F	First terms  x^3

                  O	Outside terms 2x

                  I	Inside term  8x^2

                  L	Last terms   16

2bc+4b-5c-10 = 2b(c + 2) - 5(c + 2 = (2b-5)(c+2)

                  F	First terms  2bc

                  O	Outside terms 4b

                  I	Inside term  -5c

                  L	Last terms   -10

 

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