SOLUTION: Let g and h be two functions defined by g(x)=x-8 h(x)=(x-5)(x-4) For any realnumber x. Find (g/x)(3) and then find all values that are NOT in the domain of (g/h). If there is

Question 480833: Let g and h be two functions defined by
g(x)=x-8
h(x)=(x-5)(x-4)
For any realnumber x.
Find (g/x)(3) and then find all values that are NOT in the domain of (g/h). If there is more than one value, separate them with commas.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
g(x) = (x-8)
h(x) = (x-5)(x-4)
(g/h)(x) = g(x) / h(x) = (x-8) / ((x-5)(x-4))
(g/h)(3) = g(3) / h(3) = (3-8) / ((3-5)(3-4)) = (-5)/((-2)(-1)) = -5/2
the domain does not include x = 5 or x = 4 because either one of those would make the denominator = 0 which leads to an undefined value for the expression.

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