SOLUTION: (2a+5)/(b+5) + (-8a+1)/(b+5) I combined the like terms in the numerator and kept the (already) common denominator: (-6a+6)/(b+5) The result can not be simplified (no com

Algebra.Com
Question 479625: (2a+5)/(b+5) + (-8a+1)/(b+5)
I combined the like terms in the numerator and kept the (already) common denominator:
(-6a+6)/(b+5)
The result can not be simplified (no common factors), but do I need to factor the numerator? (Or is the answer correct as written?)
If so, would both these answers be correct?
[-6(a - 1)]/(b+5) or [6(-a + 1)] / (b+5)
Thanks for your help.

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
yuo did it right, the answer is:
or

RELATED QUESTIONS

If a/b=6/7 and a/c=2/5,what is the value of 3b+c in terms of a? (A)12a (B)9a (C)8a... (answered by stanbon,Alan3354)
write the equation without fractions: 3+a/2a=1/3+5/6a. a. 3+a=1+5 b. 9+3a=2a+5... (answered by MathLover1)
1. (6-3i)/(2+i) a. Multiply the numerator and the denominator by the conjugate. show... (answered by Alan3354)
1. (6-3i)/(2+i) a. Multiply the numerator and the denominator by the conjugate. show (answered by Alan3354)
To rationalize 4+3i/1+2i, multiply the numerator and the denominator by? a. 2+i b. 4-i (answered by stanbon)
which is the least common multiple of 4a^3b and 8a^2b^5? A. 4a^2b B. 8ab C. 8a^3b^5... (answered by scmiller777)
If the numerator and denominator of a fraction are each increased by 1, the result is... (answered by josgarithmetic)
Use the method of substitution to solve the system of linear equations. 6a=5-b... (answered by Alan3354)
I think I'm doing this right, but I want to make sure. The instructions are: Simplify... (answered by stanbon)