SOLUTION: given that {{{x^4+4y^4=(x^4+4x^2y^2+4y^4)-4x^2y^2}}}, I need to complete the factorization of {{{x^4+4y^4}}} by using the difference of squares Thanks!

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: given that {{{x^4+4y^4=(x^4+4x^2y^2+4y^4)-4x^2y^2}}}, I need to complete the factorization of {{{x^4+4y^4}}} by using the difference of squares Thanks!      Log On


   



Question 479310: given that x%5E4%2B4y%5E4=%28x%5E4%2B4x%5E2y%5E2%2B4y%5E4%29-4x%5E2y%5E2, I need to complete the factorization of x%5E4%2B4y%5E4 by using the difference of squares
Thanks!

Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
complete the factorization of x^4+4y^4 by using the difference of squares
Thanks!
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x^4+4y^4 = x^4-(-4y^4)
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= (x^2-2iy^2)(x^2+2iy^2)
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Cheers,
Stan H.
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Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
given that x%5E4%2B4y%5E4=%28x%5E4%2B4x%5E2y%5E2%2B4y%5E4%29-4x%5E2y%5E2, I need to complete the factorization of x%5E4%2B4y%5E4 by using the difference of squares
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= %28x%5E2+%2B+2y%5E2+%2B+2xy%29%2A%28x%5E2+%2B+2y%5E2+-+2xy%29
or %28x%5E2+%2B+2xy+%2B+2y%5E2%29%2A%28x%5E2+-+2xy+%2B+2y%5E2%29