SOLUTION: Andrew factored the expression 28x^3-42x^2+35x as 7x(4x^4+6x-5). But when Melissa applied the distributive law and multiplied out 7x(4x^2+6x-5), she got 28x^3+42x^2-35x ; thus, And

Question 474974: Andrew factored the expression 28x^3-42x^2+35x as 7x(4x^4+6x-5). But when Melissa applied the distributive law and multiplied out 7x(4x^2+6x-5), she got 28x^3+42x^2-35x ; thus, Andrew�s solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state. Please show all work.

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Andrew factored the expression 28x^3-42x^2+35x as 7x(4x^2+6x-5). But when Melissa applied the distributive law and multiplied out 7x(4x^2+6x-5), she got 28x^3+42x^2-35x ; thus, Andrew�s solution does not appear to check. Why is that?
:
28x^3 - 42x^2 + 35x as 7x(4x^2 + 6x - 5),
the signs are wrong, should be:
28x^3 - 42x^2 + 35x = 7x(4x^2 - 6x + 5)
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