3x³–x²–3x+1 Factor x² out of the first two terms: x²(3x-1)-3x+1 Factor -1 out of the last two terms: x²(3x-1)-1(3x-1) Factor out (3x-1) (3x-1)(x²-1) Factor the second parenthesis as the difference of two squares: (3x-1)(x-1)(x+1) Set each factor = 0 3x-1=0 x-1=0 x+1=0 3x=1 x=1 x=-1 x=The zeros are , 1, and -1 Edwin