SOLUTION: divide:
(42b^3+16b^2+40b+36)/(6b+4)
Thank you!
Algebra.Com
Question 470803: divide:
(42b^3+16b^2+40b+36)/(6b+4)
Thank you!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Use polynomial long division to get
So
RELATED QUESTIONS
Can someone please help me with this problem?? Thank you so much in advance!!!
Divide: (answered by JimboP1977)
Divide... (answered by rwm)
Factor completely... (answered by Alan3354)
I am having so much trouble with 3 problems. I keep doing them over and over and coming... (answered by richwmiller)
Hi everyone, please help me on this problem:
Divide:
(24b^3+16b^2+24b+40)divide by... (answered by rwm)
1: t^3 - 2t^2 -63t factor the trinomial
2: (42b^3 + 23b^2 + 38b + 41) / (answered by vleith)
Divide
(42b^3+23b^2+32b+41) divided by (6b+5)
not sure which is the ans. if at all... (answered by PRMath)
How do you do 16b squared minus 40b plus... (answered by Alan3354,ReadingBoosters)
I am supposed to divide the polynomial:
(42b^3+23b^2+32b+38)/(6b+5)
The answer I... (answered by stanbon)