SOLUTION: Can someone help me with this problem? What values for x must be excluded in the following fraction? x-3/(4x-5)(x+1)

Question 47079: Can someone help me with this problem?
What values for x must be excluded in the following fraction?
x-3/(4x-5)(x+1)
Found 2 solutions by mathchemprofessor, wuwei96815:
Answer by mathchemprofessor(65) (Show Source): You can put this solution on YOUR website!
In the fraction,,x-3/(4x-5)(x+1),
denominator is (4x-5)(x+1).
To make it zero, either 4x-5=0 or x+1=0
The excluded values for x are -1 and 5/4

Answer by wuwei96815(245) (Show Source): You can put this solution on YOUR website!
I would guess x=5/4 or x=-1 because either value would result in a denominator of 0.
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