SOLUTION: (y^3-3y^2)/(y^2+2y-15)=(13y-40)/(y+5)
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Question 469553
:
(y^3-3y^2)/(y^2+2y-15)=(13y-40)/(y+5)
Answer by
ewatrrr(24785)
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Hi,
y^2 = 13y - 40
y^2 - 3y + 40 = 0
factoring
(y-8)(y-5) = 0
(y-8)= 0 y = 8
(y-5)= 0 y = 5
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