SOLUTION: Hello. Can you please help me fully factorize these: 1. 3x^2-3(x+2)^2 2. 12x^2-27(3+x)^2 Thank you so much!

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Question 466681: Hello. Can you please help me fully factorize these:
1. 3x^2-3(x+2)^2
2. 12x^2-27(3+x)^2
Thank you so much!

Found 2 solutions by mananth, Edwin McCravy:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!


difference of two squares



3*2*(-2)(x-2)
-12(x-2)

2. 12x^2-27(3+x)^2




Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
You're studying factoring the difference of two squares

    A² - B² = (A - B)(A + B)

-------------------------------------

1.    3x² - 3(x+2)²

First take out the common factor 3, using []'s

  3[x² - (x+2)²]   

Now factor the expression in the []'s as the difference 
of two squares:

 3[x - (x+2)][x + (x+2)]

Simplify:

 3[x - x - 2][x + x + 2]

 3[-2][2x+2]

Multiply the 3 by the -2 and also take out common
factor 2

   -6[2(x+1)] 

    -12(x+1)

That's it.

---------------------------------

2.    12x²-27(3+x)²


   First take out the common factor 3, using []'s

  3[4x² - 9(3+x)²]   

Now factor the expression in the []'s as the difference 
of two squares:

 3[2x - 3(3+x)][2x + 3(3+x)]

Simplify:

 3[2x - 9 - 3x][2x + 9 + 3x]

 3[-x - 9][5x + 9]

Take out common factor -1 in [-x - 9]

 3(-1)[x + 9][5x + 9]
 
   -3(x + 9)(5x + 9)

That's it.

Edwin

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