SOLUTION: I have to use the binomial theorem to find the 9th term of (a/b + b/a)^11 instead of expanding the whole thing out. I got as far as 165*(a/b)^3*(b/a)^8 but am not sure about simpli

SOLUTION: I have to use the binomial theorem to find the 9th term of (a/b + b/a)^11 instead of expanding the whole thing out. I got as far as 165(a/b)^3(b/a)^8 but am not sure about simpli

Question 464568: I have to use the binomial theorem to find the 9th term of (a/b + b/a)^11 instead of expanding the whole thing out. I got as far as 165*(a/b)^3*(b/a)^8 but am not sure about simplifying the fractions (I have always struggled with fractions). Is the answer I gave enough or do I need to go further, and if so, please help!
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!

ans:
165*(a/b)^3*(b/a)^8
= 165*(b/a)^5

RELATED QUESTIONS
(A-B)^40 So I do not know if this would follow the binomial expansion theorem? but I... (answered by richwmiller)