SOLUTION: find the vertex, the line of symmetry, and the maximum or minimum value of: f(x)= -2x^2 + 2x + 5

Question 462662: find the vertex, the line of symmetry, and the maximum or minimum value of: f(x)= -2x^2 + 2x + 5
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find the vertex, the line of symmetry, and the maximum or minimum value of: f(x)= -2x^2 + 2x + 5
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f(x)= -2x^2 + 2x + 5
Standard form for a parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the steepness of the curve.
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for given problem
y=-2x^2+2x+5
complete the square
y=-2(x^2-x+1/4)+5+1/2
y=-2(x-1/2)^2+11/2
This equation is a parabola which opens downwards with a vertex at (1/2,11/2). Line of symmetry, x=1/2. Maximum value=11/2
see graph as a visual check on the answers
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