SOLUTION: y^4+24y^2-25=0 Solve the polynomial equation by indicating first set of solutions and the second set.

Question 462173: y^4+24y^2-25=0 Solve the polynomial equation by indicating first set of solutions and the second set.
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
y^4 + 24y^2 - 25 = 0
(y� + 25)(y� - 1) = 0 {factored into two binomials}
y� + 25 = 0 or y� - 1 = 0 {set each factor equal to 0}
y� = -25 or y� = 1 {subtracted 25 and added 1 respectively}
y = �√-25 or y = �√1 {took square root of both sides in each equation}
y = �√-1 √25 or y = �1 {broke -25 into 25 and -1 and evaluated √1 to be 1}
y = �5i or y = �1 {evaluated √-1 to be i}
www.algebrahouse.com
RELATED QUESTIONS
solve the equation 2x^2-3x+1=0 and present solutions in solutions set... (answered by checkley77)

I've tried to work this out, I have one answer to the solution set, and I thought I had... (answered by stanbon)

I have a set of equations and need to solve and graph. I have done the first equation but (answered by Earlsdon)

The first of two numbers minus four times a second number is at least -4. Three times the (answered by ankor@dixie-net.com)

Find the real solutions of the following equation. The solution set is? t^1/2 -... (answered by Fombitz)

Select any two integers between -12 and +12 which will become solutions to a system of... (answered by richwmiller)

Solve x^2+6x-2=0 by graphing. If the solutions are not exact,estimate the answers by... (answered by checkley75)

Solve the system of equations x+y=6 x-y=-7 Set the first equation to: x=6-y, and... (answered by student100)

Hello out there,I really need some help really bad with some tough problems,The first one (answered by stanbon)