SOLUTION: hi im not really sure if my question would be in this category but if you could help me the best way you can that would mean a lot to me thanks [3x-2/2x^2-5x-3]-[1/x-3] can

Question 458657: hi im not really sure if my question would be in this category but if you could help me the best way you can that would mean a lot to me thanks

[3x-2/2x^2-5x-3]-[1/x-3]
can you please walk me through this im clueless
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
[3x-2/2x^2-5x-3]-[1/x-3]

----
Factor where you can:
= [3x-2/(x-3)(2x+1)]-[1/x-3]
-------
Least common denominator: (x-3)(2x+1)
-----------
Rewrite each fraction with the lcd as its denominator:
= [(3x-2)/lcd] - [(2x+1)/lcd]
-----------
Combine the numerators over the lcd:
= [3x-2-2x-1]/lcd
---
= (x-3)/[(x-3)(2x+1)]
----
Cancel the common (x-3) factor to get:
----
= 1/(2x+1)
===================
Cheers,
Stan H.

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