SOLUTION: (a + b)^2 - (a - b)^2
= ab^2 + ab^2
= 2ab + 2ab
= 4ab
would you say this equation is solved correctly?
I'm concerned that I might have skipped a step.
Algebra.Com
Question 45516: (a + b)^2 - (a - b)^2
= ab^2 + ab^2
= 2ab + 2ab
= 4ab
would you say this equation is solved correctly?
I'm concerned that I might have skipped a step.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(a + b)^2 - (a - b)^2
=a^2+2ab+b^2 -[a^2-2ab+b^2]
=4ab
Cheers,
Stan H.
RELATED QUESTIONS
How would I multiply and simplify... (answered by TimothyLamb)
The following appears to prove that any two numbers are equal. Obviously it is wrong; can (answered by Edwin McCravy)
The following appears to prove that any two numbers are equal. Obviously it is wrong; can (answered by vleith)
The radical √(85+√2736) can be expressed as √a + √b, where a < b. What is the... (answered by ikleyn,math_tutor2020)
If a=log4 of 7 and b=log7 of 5, then in terms of a and b, log5 is equal to:
a) ab... (answered by greenestamps)
(a^2+b^2+2ab)-(a^2+b^2-2ab) (answered by jim_thompson5910)
If {{{a^2-2ab+b^2=36}}} and {{{a^2-3ab+b^2=22}}} find... (answered by richard1234)
I am having a bit of trouble with what I think is a fairly basic equation. -4ab*1/2ba^2... (answered by KMST)
a^2... (answered by jim_thompson5910)