SOLUTION: findall the real zeros of the function
f(x)=x^3-3x^2-x+3
Algebra.Com
Question 451820: findall the real zeros of the function
f(x)=x^3-3x^2-x+3
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
findall the real zeros of the function
f(x)=x^3-3x^2-x+3
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The sum of the coefficients is zero, so x = 1 is a root.
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1)....1....-3....-1....3
.......1.....-2....-3...|..0
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Quotient: x^2-2x-3
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Factor:
(x-3)(x+1) = 0
x = 3 or x = -1
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Final Answer:
x = 1, x = -1, x = 3
========================
Cheers,
Stan H.
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