# SOLUTION: The length of a rectangle flower garden is three feet more than its width. The area is 70 square feet. Using an algbriac equation find the length and the width of the flower gard

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: The length of a rectangle flower garden is three feet more than its width. The area is 70 square feet. Using an algbriac equation find the length and the width of the flower gard      Log On

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 446907: The length of a rectangle flower garden is three feet more than its width. The area is 70 square feet. Using an algbriac equation find the length and the width of the flower garden. Would I use width = x and length = x+3 = to 70? Is that how I would set this equation up? Answer by nerdybill(6948)   (Show Source): You can put this solution on YOUR website!The length of a rectangle flower garden is three feet more than its width. The area is 70 square feet. Using an algbriac equation find the length and the width of the flower garden. . Let x = width then because "length of a rectangle flower garden is three feet more than its width" we get x+3 = length (basically, what you had) . Now, you have to apply your knowledge of the area of any rectangle: area = width * length giving you your equation: 70 = x(x+3) now we solve for x: 70 = x(x+3) 70 = x^2+3x 0 = x^2+3x-70 0 = (x+10)(x-7) x = {-10, 7} we can throw out the negative solution (extraneous) since it doesn't make sense leaving: x = 7 feet (width) . Length: x+3 = 7+3 = 10 feet