SOLUTION: (10x4-6x-15+5x3) divide(/) (2x+1)

Algebra.Com
Question 446485: (10x4-6x-15+5x3) divide(/) (2x+1)
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
(10x^4-6x-15+5x^3)/(2x+1)
----
Using sythetic division:
-1/2)....5....5/2....0....-3....-15/2
..........5.....0.....0.....-3...|..-6
Quotient: 5x^3-3
Remainder: -12
==================
Cheers,
Stan H.

RELATED QUESTIONS

please add the following (8x4 – 3x2 + 6x + 1), (5x3 – 4x2 - 2x + 2) and (-2x4 + 6x -... (answered by praseenakos@yahoo.com)
Consider the following. (5x3 + 6x + 256) (x + 4) Use synthetic division to... (answered by nyc_function)
(4x^3+6x^2-2x+3)/(2x-1)... (answered by jim_thompson5910)
Divide 5x3 – 5x + 1 by x – 3 EXPLAIN WHAT YOU ARE DOING (answered by stanbon)
Divide... (answered by atif.muhammad)
Divide this trinomial... (answered by Earlsdon)
Polynomials Divide 2x-3√8x³-6x²-7x+1 (answered by Alan3354,josgarithmetic)
divide (14x3rd... (answered by Alan3354)
5x3-7x2+3x+2byx-1 (answered by ikleyn)