SOLUTION: Use Descarte's rule of signs to determine the number of possible positive, negative, and nonreal complex solutions of the equation. Please help me. � 4x^3-6x^2+x-3=0

Question 441645: Use Descarte's rule of signs to determine the number of possible positive, negative, and nonreal complex solutions of the equation. Please help me.
� 4x^3-6x^2+x-3=0
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
There are 3 variations in signs ==> there could be 3 positive real roots, or just 1 positive real root.

Now when x is replaced by -x, the equation becomes , no variation in signs, hence there are no negative real roots.
Hence, either there 3 positive real roots,
OR
1 positive real root and 2 distinct complex roots.
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