SOLUTION: how do i solve 5 over 2x-12 - 20 over x squared-4x-12?

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 Question 440425: how do i solve 5 over 2x-12 - 20 over x squared-4x-12?Found 2 solutions by stanbon, lwsshak3:Answer by stanbon(57203)   (Show Source): You can put this solution on YOUR website!how do i solve 5 over 2x-12 - 20 over x squared-4x-12? --------------------- 5/(2x-12) - 20/(x^2-4x-12) ---- Factor: 5/(2(x-6)) - 20/[(x-6)(x+2)] --- lcd: 2(x+2)(x-6) --- Rewrite each fraction with the lcd as its denominator: --- [5(x+2)]/lcd - [20(2)]/lcd ---------------------- Combine the numerators over the lcd: ----- [5x+10-40]/lcd ---- [5x-30]/lcd --- [5(x-6)]/[2(x+2)(x-6)] --- Cancel x-6 ----- = 5/[2(x+2)] ================ Cheers, Stan H. Answer by lwsshak3(6456)   (Show Source): You can put this solution on YOUR website!how do i solve 5 over 2x-12 - 20 over x squared-4x-12? .. 5/(2x-12)-20/(x^2-4x-12) 5/2(x-6)-20(x-6)(x+2) LCD=2(x-6)(x+2) multiply both terms by the LCD and divide the result by the LCD (5(x+2)-20*2)/2(x-6)(x+2) (5x+10-40)/2(x-6)(x+2) 5x-30/2(x-6)(x+2) 5(x-6)/2(x-6)(x+2) cancel out (x-6) 5/2(x+2) (ans)