SOLUTION: When we factor a problem like X^2+5x+6, we get two sets of parenthesis, (x + 3) (x + 2). Why do we separate our factoring with these parenthesis? Does this have anything to do wit

Question 436399: When we factor a problem like X^2+5x+6, we get two sets of parenthesis, (x + 3) (x + 2). Why do we separate our factoring with these parenthesis? Does this have anything to do with being able to solve the problem?

Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
It separates because the polynomial can be expressed as a product. We use parentheses so it doesn't look like

x + 3 * x + 2

which is ambiguous (and actually equals x + 3x + 2 by order of operations). To find the roots, we can set both equations to zero, as the entire expression must be 0. Hence, either x+3 = 0 or x+2 = 0, which implies x = -3 or -2.
RELATED QUESTIONS
Please help me solve this problem. Make sure to superscript all exponents. All... (answered by eperette)

The general equation os a quadratic polynomial is p(x)=ax(squared)+bx+c with a,b,c all... (answered by longjonsilver)

Please tell me if my process is right or wrong. lim x->-∞... (answered by Fombitz)

My son is learning factoring polynomials and he has a question that he is confused about. (answered by MathLover1,ikleyn,greenestamps)

We learned how to factor trinomials awhile ago, by unfoiling like {{{x^2+2x-3}}} would be (answered by Stitch)

Why we should solve like this??? If {{{CosX = -1/2}}} {{{CosX = Cos(2(pi)/3)}}}... (answered by Alan3354)

With the problem: {{{ 2(x-5)(2x+3)+2(x-5)^2 = 0 }}} Why do we factor out the 2(x-5)?... (answered by Fombitz)

I'm having issues with these types of problems sinking in. -5x+3=x^2+2x, -5x+3-x^2+2x=0... (answered by josgarithmetic,addingup,ikleyn)