SOLUTION: Graph f(x) = -x^2+4x-3, labeling the y-intercept, vertex, and axis of symmetry.

Question 43480: Graph f(x) = -x^2+4x-3, labeling the y-intercept, vertex, and axis of symmetry.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Graph f(x) = -x^2+4x-3, labeling the y-intercept, vertex, and axis of symmetry

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=4 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1, 3. Here's your graph:

Y=intercept= (0,-3)
Axis of symmetry = x=-b/2a=-4/(-2)=2
Vertex is on the graph.
Cheers,
Stan H.
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