SOLUTION: factor as the sum of two cubes: 8b^3+1/27 (faction) I know (a+b)(a^2-ab+b^2) may problem is the faction of 1/27

SOLUTION: factor as the sum of two cubes: 8b^3+1/27 (faction) I know (a+b)(a^2-ab+b^2) may problem is the faction of 1/27

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Question 432258: factor as the sum of two cubes:
8b^3+1/27 (faction)
I know (a+b)(a^2-ab+b^2)
may problem is the faction of 1/27
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
(1/3)^3 = 1/27
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